CHM 2045C    Module Two Sample Exam

Module Two: ChemMath and Measurement (Chapter 1)

A. _____(03) Significant Figures-Section 1.8  Answers abc

B. _____(03) Round Off/Math of Significant Figures-Section 1.8

C. _____(04) Scientific Notation  Section 1.8

D. _____(04) Metric Basic Units /Numerical Prefixes-Section 1.6 Table 1.3. de

E. _____(05) Metric System Conversion Factors-Sect 1.6

F. _____(10) Unit Analysis Problems Section 1.8 Answers fh

G. _____(08) Temperature Conversion 1.6  gh

H. _____(08)  Density/Specific Gravity Calculations 1.4

M. _____(10) Multiple Choice(Measurement) Chapter 1&2 (Answers at the Bottom)

_______(55) Total = ______%

Module Two-Part A: Significant figures (1.7)     3 points

In the blank, state the number of significant figures in each of the following measurements:

____1.  0.05 mL                                            _____4.  1000 g

____2.  250.0 cm                                          _____5.  0.00006500 moles

____3.   456,000,000 people                   _____6. 0.00200 kg

Module Two-Part B: Rounding Off & Arithmetic Operations of Sign. Figures     3 points

Round off the following numbers to three significant figures:

(1) 1.598 x 106= _____________ (2) 0.000 000 484 500 = _________________

Perform the following addition/multiplication operations and express the answer using the proper units and significant figures:

(3)    4       mL                         (4)    16.5 cm             (5)       12.0  g

16.3    mL                                         X    1.7 cm                    X 1.00 g

+    0.953 mL

Module Two-Part C: Exponential Numbers and Scientific Notation 3 points

(1.6 & 1.&) Express the following ordinary numbers in scientific notation (If greater than three significant figures, round off to three significant figures:

(1) 1,010,100,000,000, 000  = ________________    (4) 0.0001198 = _____________

(2) 0.000 000 000 000 019   =  ________________   (5) 1,000,000 = ______________

(3)                           456,789   = _________________  (6) 0.000200  = ______________