**CHM 2045C Module 4 Part II Sample Exam ****Answers
**Chapter
10 Sample Multiple Choice Answers

**1. ****The
correct answer is:
**

Explanation:

A sharing of electrons

Solution Reference:

Page 439, Orbitals and Bonding Theories

**2.** **The
correct answer is:
**

Explanation:

In covalent compounds, bromine and chlorine would have the tendency to form one bond, as each has one half-filled orbital.

Solution Reference:

Page 439, Orbitals and Bonding Theories

**3.****The
correct answer is:
**

Solution Reference:

Page 442, Hybridization Involving s and p Atomic Orbitals

**4.****The
correct answer is:
**

Solution Reference:

Page 442, Hybridization Involving s and p Atomic Orbitals

**5.****The
correct answer is:
**

Explanation:

There are four regions of electron density about each nitrogen, so nitrogen atoms can be described as being sp

Solution Reference:

Page 442, Hybridization Involving s and p Atomic Orbitals

**6.The**** correct answer is:
3 only
Explanation:
Solution Reference:
Page 442, Hybridization Involving s and p
Atomic Orbitals**

**7.**

**The
correct answer is:
**

Explanation:

Phosphine has a pyramidal shape and the phosphorus atom is hybridized sp

Solution Reference:

Page 442, Hybridization Involving s and p Atomic Orbitals, and Page 423, Molecular Polarity

**8.****The
correct answer is:
**NH

Explanation:

Each nitrogen atom has four pairs of electrons surrounding it.

Solution Reference:

Page 442, Hybridization Involving s and p Atomic Orbitals

**9.****The
correct answer is:
**

Explanation:

The P atom has five regions of electron density. Thus, there must be five hybrid orbitals.

Solution Reference:

Page 449, Hybridization Involving s, p, and d Atomic Orbitals

**10. ****The
correct answer is:
**

Solution Reference:

Page 442, Hybridization Involving s and p Atomic Orbitals.

**11. **

**The
correct answer is:
**

Explanation:

Draw the Lewis structures and find the number of regions of electron density, or make an energy level diagram.

Solution Reference:

Page 492, Hybridization Involving s and p Atomic Orbitals

**12. **

**The
correct answer is:
**

Explanation:

Solution Reference:

Page 452, Multiple Bonds

**13. **

**The
correct answer is:
**

Solution Reference:

Page 452, Multiple Bonds

**14. **

**The
correct answer is:
**

Explanation:

Both NO

Solution Reference:

Page 452, Multiple Bonds

**15. **

**The
correct answer is:
**

Solution Reference:

Page 452, Multiple Bonds

**16. ****The
correct answer is:
**

Explanation:

Solution Reference:

Page 452, Multiple Bonds

**17. ****The
correct answer is:
**

Explanation:

Bond Orders:

O

O

O

Solution Reference:

Page 459, Molecular Orbital Theory

**18. ****The
correct answer is:
**

Explanation:

Bond Orders:

F

CN

NO

Solution Reference:

Page 459, Molecular Orbital Theory

**19. ****The
correct answer is:
**

Solution Reference:

Page 459, Molecular Orbital Theory

**20. ****The
correct answer is:
**

Solution Reference:

Page 470, Metals and Semiconductors

**21. **

**The
correct answer is:
**

Solution Reference:

Page 459, Molecular Orbital Theory

**22. ****The
correct answer is:
**

Explanation:

Which species has 10 valence electrons?

Solution Reference:

Page 459, Molecular Orbital Theory

**23. ****The
correct answer is:
**

Solution Reference:

Page 459, Molecular Orbital Theory

**24. ****The
correct answer is:
**

Solution Reference:

Page 459, Molecular Orbital Theory

**25.****The
correct answer is:
**

Solution Reference:

Page 459, Molecular Orbital Theory