CHM
2045C Module Five Sample
Exam
Module
Five (Question #70 p 171 Kotz
6th)
Part
N Multi-step
Synthesis Stoichiometry 4
points
Potassium perchlorate may be made by the following series of
reactions:
Cl2 + 2
KOH ----> KCl + KClO + H2O
3 KClO
-----> 2 KCl + KClO3
4 KClO3 -----> 3
KClO4 + KCl
How much Cl2 is needed to prepare 100 g of Potassium perchlorate KClO4 by the above sequence?
____?_____ g Cl2 = 100
g KClO4
3 moles KClO4 = 4
moles KClO3
1 mole KClO3 = 3 mole KCLO
1 mol KClO = 1 mole Cl2
Other Problems: Problem #73 Page
171 Kotz 6th Edition