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Chapter 17 - Practice Multiple
Choice Test 2 |
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1. Which of the following changes requires an
oxidizing agent? |
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a. |
NH3
--> NH4+ |
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b. |
N2H4
--> N2 |
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c. |
NO3-
--> N2O |
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d. |
NO2-
--> N2O3 |
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e. |
NO2
--> N2O4 |
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2. In the
balanced equation 2MnO4- + 5C2O42-
+ 16H+ --> 2Mn2+ + 10 CO2 + 8H2O
the reducing agent is |
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a. |
MnO4-. |
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b. |
C2O42-. |
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c. |
H+. |
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d. |
Mn2+. |
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e. |
CO2. |
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4FeCr2O4 + 8Na2CO3
+ 7O2 + 4H2SO4 --> 4Na2Cr2O7
+ 2Fe2O3 + 4H2O + 8CO2 + 4Na2SO4
The reducing agent is ______ and the oxidation product(s) is (are) ______. |
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a. |
Na2CO3;
CO2 and Na2Cr2O7 |
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b. |
FeCr2O4;
Fe2O3 and Na2Cr2O7 |
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c. |
FeCr2O4;
Fe2O3 and H2O |
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d. |
FeCr2O4;
Fe2O3, Na2Cr2O7 and H2O |
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e. |
Na2CO3;
CO2 and H2O |
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4. In
which of the following species does the underlined element have an oxidation
number of +2? |
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a. |
Zn(OH)42-
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b. |
CrO2Cl2
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c. |
HNO2 |
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d. |
PH4+
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e. |
NO2 |
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5. All of the following half-reactions are balanced
EXCEPT |
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a. |
2H2O + 2e --> H2 + 2OH- |
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b. |
NO3- + 4H+ + 3e --> NO
+ 2H2O |
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c. |
2Ta + 5H2O --> Ta2O5 +
10H+ + 10e |
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d. |
H3PO3 + H2O --> H3PO4
+ 2H+ + 2e |
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e. |
Fe3+ --> Fe2+ + e |
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6. I2 + 6H2O -->
2IO3- + 12H+ + ______ e |
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a. |
2 |
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b. |
6 |
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c. |
8 |
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d. |
10 |
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e. |
12 |
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7. Glycidol
can be oxidized in acid solution to malonic acid.
When the half-reaction C3H6O2 --> C3H4O4
is balanced, there are |
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a. |
2H+ + 2e on the
left-hand side. |
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b. |
2H+ + 4e on the
right-hand side. |
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c. |
4H+ + 4e on the
right-hand side. |
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d. |
4H+ + 4e on the
left-hand side. |
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e. |
6H+ + 6e on the
right-hand side. |
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a. |
1 |
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b. |
2 |
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c. |
4 |
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d. |
6 |
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e. |
8 |
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9. For the reaction between permanganate
ion and sulfite ion in basic solution, the unbalanced equation is MnO4-
+ SO32- --> MnO2 + SO42-.
When
this equation is balanced using the smallest whole number coefficients
possible, the number of |
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a. |
two on the right. |
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b. |
two on the left. |
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c. |
three on the right. |
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d. |
four on the right. |
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e. |
four on the left. |
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10. Which of the following processes
could occur at the anode of an electrochemical cell? |
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a. |
Cu2+ + 2e --> Cu |
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b. |
Zn2+ + 2e --> Zn |
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c. |
Cu --> Cu2+ + 2e |
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d. |
Zn --> Zn2+ + 2e |
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e. |
both c and d |
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11. Calculate the standard Gibbs free
energy change for the reaction: |
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a. |
765 kJ |
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b. |
-269 kJ |
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c. |
-404 kJ |
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d. |
-765 kJ |
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e. |
-807 kJ |
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12. A cell with a potential of 0.15 V
has the cell reaction 2Cu2+(aq) + H2 --> 2Cu+(aq) + 2H+(aq) If
the concentrations of ions were 1.0 molar and the pressure of H2
were 1.0 atmosphere, then E° for the half reaction Cu2+(aq) + e --> Cu+(aq)
would
be |
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a. |
-0.075 V. |
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b. |
-0.15 V. |
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c. |
0.075 V. |
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d. |
0.15 V. |
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e. |
0.30 V. |
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13. If the value of -1.00 volts was
assigned to the standard hydrogen half-cell instead of the currently accepted
value of zero 2H+(aq) + 2e --> H2
E? = -1.00 V then
all reduction half-cell potentials and all cell potentials would respectively |
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a. |
decrease by 1.00 V and decrease
by 1.00 V. |
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b. |
decrease by 1.00 V and remain unchanged. |
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c. |
decrease by 1.00 V and increase
by 1.00 V. |
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d. |
increase by 1.00 V and increase
by 1.00 V. |
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e. |
increase by 1.00 V and decrease
by 1.00 V. |
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14. Given the standard reduction
potentials
what is the standard cell
potential for the reaction |
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a. |
-1.08 V |
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b. |
-0.40 V |
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c. |
0.40 V |
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d. |
1.08 V |
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e. |
2.50 V |
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. 15.
An element or ion that will oxidize iron but will not oxidize mercury is |
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a. |
Al3+. |
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b. |
Sn2+. |
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c. |
Br-. |
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d. |
Cu. |
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e. |
Al. |
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16.
The strongest reducing agent of this series is |
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a. |
H2. |
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b. |
Br2. |
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c. |
Br-. |
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d. |
Al. |
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e. |
Al3+. |
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17.
An element that would dissolve in HNO3 without the evolution of H2
would be |
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a. |
Fe. |
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b. |
Sn. |
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c. |
Cu. |
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d. |
Al. |
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18. The voltage produced in the reaction
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a. |
the metal used as the anode. |
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b. |
the concentration of Fe2+. |
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c. |
the concentration of Cu2+. |
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d. |
the temperature. |
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e. |
the size of the anode. |
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19. From a consideration of the Nernst equation |
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a. |
E = 1.0. |
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b. |
E = E°. |
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c. |
E = 0. |
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d. |
E° = 0. |
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e. |
Kc = Q. |
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20. For a certain oxidation-reduction
reaction, E° is negative. This means that |
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a. |
DG° is negative and K is less than 1. |
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b. |
DG° is negative and K is greater than 1. |
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c. |
DG° is zero and K is greater than 1. |
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d. |
DG° is positive and K is greater than 1. |
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e. |
DG° is positive and K is less than 1. |
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21. A cell consists of a magnesium
electrode immersed in a solution of magnesium chloride and a silver electrode
immersed in a solution of silver nitrate. The two half-cells are connected by
means of a salt bridge. It is possible to increase the voltage of the cell by
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a. |
addition of sodium chloride to both half-cells. |
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b. |
increasing the Mg2+ concentration and decreasing the Ag+
concentration. |
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c. |
increasing the size of the Mg electrode and decreasing the size of
the Ag electrode. |
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d. |
decreasing the size of the Mg electrode and increasing the size of
the Ag electrode. |
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e. |
decreasing the Mg2+ concentration. |
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22. A copper electrode in CuSO4
solution is connected by a wire to a silver electrode in a
AgNO3 solution. The two solutions are also joined by a salt bridge
Current is allowed to flow through the cell until the mass of the silver
electrode has changed by 108 g. During this time the mass of the copper
electrode will |
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a. |
decrease by 108 g. |
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b. |
increase by 108 g. |
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c. |
increase by 31.8 g. |
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d. |
decrease by 31.8 g. |
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e. |
decrease by 63.5 g. |
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23. A steady current of 10.0 amp flowing
for 965 sec. corresponds to |
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a. |
9650 electrons. |
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b. |
0.100 Faraday. |
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c. |
0.100 volt. |
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d. |
0.100 coulomb. |
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e. |
None of these. |
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24. When a dilute aqueous solution of Li2SO4
is electrolyzed, the products formed at the anode and cathode, respectively,
are |
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a. |
O2 and H2. |
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b. |
H2 and O2. |
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c. |
O2 and H+. |
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d. |
H2 and |
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e. |
O2 and Li. |
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25. The following reaction takes place
in a lead storage battery. PbO2(s)
+ Pb(s) + 2H2SO4(aq) --> 2PbSO4(s) + 2H2O(l)
Which
state is true? |
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a. |
The concentration of H2SO4
increases as the battery discharges. |
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b. |
Pb is formed at the anode during discharging. |
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c. |
PbO2 is formed at the
anode during charging. |
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d. |
The mass of Pb
decreases during charging. |
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e. |
The mass of PbSO4
remains constant during charging and discharging. |