CHM 2046C        Module Ten-Chapter 16 Sample Test

Module Ten: Chemical Equilibria Chapter 16

Possible

Actual

 

A.   Equilibrium Constant Derivation from Reaction Rates Lecture

10

 

 

B.   Writing Equilibrium Constant Expressions Section 16.2  p760-1

10

 

 

C.  Meaning  of the Equilibrium Constant: K;  Section 16.2 p765-7

10

 

 

D.  Meaning  of the Equilibrium Quotient: Q;   Section 16.2 p767-9

10

 

 

E.   Determination of Equilibrium Constants from Lab Data Section 16.3-16.4

10

 

 

F.   La Chatelier's Principle Problems Section 16.6                                     

10

 

 

G.   Determination of Equilibrium Conc from Kc Problems Section 16.4-16.5

10

 

 

H.   Disturbing a Chemical Equilibrium Section 16.6

10

 

 

I.    Discussion Questions Chapter 16

10

 

 

J.    Key Terms - Chapter 16 & More about Equations & Eq Coefficients 16.5

10

 

 

M.   Multiple Choice - Chapter 16                                      

25

 

 

Module Ten Total: 

125

 

 

Part A: Equilibrium Constant Derivation                       10 points

Derive the equilibrium constant expression

 

           [C]c [D]d

Kc = ---------------

           [A]a [B]b

 

from the rate expressions of the following reversible reaction:

 

aA   +     bB    ç è      cC     +     dD

 

Part B: Equilibrium Constant Expressions            10 points

Write equilibrium constant expressions, Kc,  for the following reactions they represent:

 

a.          PCl3 (g)        +      Cl2 (g)     ç è   PCl5  (g)

 

Kc =

 

b.         2 NOCl (g)            ç è       2   NO (g)    +     Cl2 (g)

 

Kc =

 

c.        4 HCl (g)      +      O2 (g)       ç è       2 H2O (g)    +    2 Cl2 (g)

 

Kc =

 

d.       CS2 (g)     +    H2 (g)   ç è      CH4 (g)     +   H2S   (g)

 

Kc =

 

e.   CaCO3 (s)     ç è      CaO (s)     +   CO2   (g)

 

Kc =

 

f.          NH3 (g)     +     H2O (l)      ç è   NH4 1+(aq) +   OH1-  (aq)

 

Kc =